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Media Geometrica a numerelor a si b


a = √3 - 1/√3
b= 1
    _            -2
2-√3


/ = supra


Răspuns :

a= 3r3/3-r3/3= 2r3/3 r-radical

Mg=r2r3/3 ×1
Mg= 3r2/r3
mg=3r6/3
mg= r6
a=√3 - 1/√3 

b=1/(2-√3) -2 =(2+√3)/(4-3) -2=2+√3 -2=√3

mg=√(√3 - 1/√3 )× √3=√(3 - 1)=√2