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2a+3b=9n+24 si5b-6c=15n+2 sa se afle a=?,c=? a,b,c apartine numerelor naturale

Răspuns :

2a=9n+24-3b.

a=9/2n+12-3/2b,b∈R, n∈R.

5b=15n+2+6c

b=3n+2/5+6/5c, c∈R, n∈R.