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3+6+9+......+2016=???

Răspuns :

[tex]\displaystyle \mathtt{3+6+9+...+2016=3(1+2+3+...+672)=3 \cdot \frac{672(672+1)}{2}= } \\ \\ \mathtt{=3 \cdot \frac{672 \cdot 673}{2} =3 \cdot 336 \cdot 673=678384}[/tex]