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Rezolvati in R ecuatia : 0,1x²-x-2,5=0

Răspuns :

[tex]0,1x^2-x-2,5=0|\cdot 10\\ x^2-10x-25=0\\ \triangle=b^2-4ac=(-10)^2-4(-25)=100+100=200\\ x_{1/2}= \frac{10\pm\sqrt{200}}{2} =5\pm5 \sqrt{2} [/tex]