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Sa se imparta nr 620 in parti invers proportional cu 2, 3, 5

Răspuns :

Fie a,b si c numerele cautate. Avem:

a+b+c=620
a/1/2=b/1/3=c/1/5=a+b+c / 1/2+1/3+1/5 = 620/31/15=20*15=300(coef de proportionalitate)
a/1/2=300, a=150
b/1/3=300, b=300*1/3=100
c/1/5=300, c= 300*1/5= 60