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aflati toate perechile de numere a,b astfel ancat
aᵇ-1=7·3²
va rog urgent!


Răspuns :

[tex] a^{b} -1= 7*3^{2} [/tex]
[tex] a^{b} -1= 7*3^{2} =\ \textgreater \ a^{b} =64[/tex]

64 | 2
32 | 2
16 | 2
  8 | 2
  4 | 2
  5 | 2

[tex]64= 2^{6} = 4^{3} = 8^{2} [/tex]

(2, 6), (4, 3), (8, 2)